
This Child Is a Legendary Sorcerer
This Child Is a Legendary Sorcerer es un drama corto de 40 episodios. Míralo gratis en DramaWatch o en ReelShort.
Cole was the undisputed Supreme Sorcerer — until he died in a cataclysmic magical war. His soul reincarnated into the body of a young boy named Leo — a boy afflicted with a Death Curse, with little time left to live. The only hope: the Starlight Potion, guarded by the arrogant Westwood family. Leo’s mother, Clara, a powerless ordinary woman, humbled herself before the Westwoods, begging for the potion to save her son.They ridiculed her. Humiliated her. But Clara never backed down. Until Leo could take it no more.Something inside Leo shattered. A pressure so immense it cracked the marble floor exploded from his tiny frame. The entire Westwood mansion trembled. Every sorcerer in the room was forced to their knees — their faces pressed to the ground, unable to breathe, unable to speak. But no one knew: Clara herself had also been struck by the Death Curse. And in the end, for the sake of her child, she gave the only life-saving potion to Leo.
Ratings & reviews
community scored
Be the first to rate This Child Is a Legendary Sorcerer.
Discussion
notes from members
Sign in to comment.
Free
Free
Free
Free
Free
Free
Free
Free
Free
Free
Free
FreePreguntas frecuentes
respuestas rápidas
¿Cómo ver This Child Is a Legendary Sorcerer?
This Child Is a Legendary Sorcerer está disponible en ReelShort. WatchDex reúne todas las apps que lo tienen, gratis y de pago.
¿Cuántos episodios tiene This Child Is a Legendary Sorcerer?
This Child Is a Legendary Sorcerer tiene 40 episodios.
¿Se puede ver This Child Is a Legendary Sorcerer gratis?
Los primeros episodios de This Child Is a Legendary Sorcerer suelen ser gratis; los siguientes pueden requerir monedas o suscripción en ReelShort.
¿Puedo ver This Child Is a Legendary Sorcerer con subtítulos en español?
This Child Is a Legendary Sorcerer está en ReelShort. Muchas apps de dramas cortos ofrecen subtítulos en español; revisa el idioma en cada app.
